Linux伊甸园论坛 » Shell编程 » 【讨论】判断某个字符串以字符开头

fush_linux 发表于 2006-8-10 17:44

【讨论】判断某个字符串以字符开头

请教下，在shell脚本中如何判断一个字符串是以字符开头，如：test001

dearvoid 发表于 2006-8-10 17:50

[code][color=blue]-(user@host:tty)-(tmp)-
[4181 0] $ [/color]var=123
[color=blue]-(user@host:tty)-(tmp)-
[4181 0] $ [/color]if [[ $var == [a-zA-Z]* ]]; then echo yes; else echo no; fi
no
[color=blue]-(user@host:tty)-(tmp)-
[4181 0] $ [/color]var=helloworld
[color=blue]-(user@host:tty)-(tmp)-
[4181 0] $ [/color]if [[ $var == [a-zA-Z]* ]]; then echo yes; else echo no; fi
yes
[color=blue]-(user@host:tty)-(tmp)-
[4181 0] $ [/color][/code]

fush_linux 发表于 2006-8-10 18:05

师兄，非常感谢！！

li-jiahuan 发表于 2006-8-10 23:33

[code]
[0 No.2008 huan@deb ~]$ case "abc123" in [a-zA-Z]*) echo Y;; *) echo N;; esac
Y

[0 No.2009 huan@deb ~]$ case "123abc" in [a-zA-Z]*) echo Y;; *) echo N;; esac
N

[0 No.2010 huan@deb ~]$              
[/code]

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