Linux伊甸园论坛 » Shell编程 » 如何去除以某些字符结尾的换行符啊？

mygod100 发表于 2008-4-16 11:03

如何去除以某些字符结尾的换行符啊？

比如有文件source.txt
[code]
abc0001
ddddd
jjjj0123
kkkkkk
dddddddddd
jjjjjjjjjjjjjjjjjjjj
[/code]
把数字结尾的换行去除，变成target.txt
[code]
abc0001ddddd
jjjj0123kkkkkk
dddddddddd
jjjjjjjjjjjjjjjjjjjj
[/code]

谢谢!

[[i] 本帖最后由 mygod100 于 2008-4-16 11:14 编辑 [/i]]

TUDOU01 发表于 2008-4-16 12:16

我也经常被这个文体困扰,可以试一下col -bx 或 dos2unix.

twf_cc 发表于 2008-4-16 18:13

不知是不是這樣?

[code]

fang@bash ~
$ cat junk
abc0001
ddddd
jjjj0123
kkkkkk
dddddddddd
jjjjjjjjjjjjjjjjjjjj

fang@bash ~
$ sed ':a;/^.*[0-9]$/N;s/\n//;ta' junk
abc0001ddddd
jjjj0123kkkkkk
dddddddddd
jjjjjjjjjjjjjjjjjjjj

fang@bash ~
$

[/code]

mygod100 发表于 2008-5-6 11:08

看了我好多天了，终于把楼上的回答给看懂了
执行老早就可以了，看懂意义那才是难啊

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