文本如下：
I'm a student.
You are a teacher.
He is a farmer.
He is a farmer.
He is a farmer.
We are workers.
将重复行找到，并删去只留一行，并且文本顺序不能改变，如何用sed实现?

[ 本帖最后由 dearvoid 于 2007-8-16 09:19 编辑 ]　　　　　　

sed可以做行比较吗　　　　　　

用 uniq 比较方便:

复制内容到剪贴板

代码:

cax@ibm:~/Desktop> cat a
I'm a student.
You are a teacher.
He is a farmer.
He is a farmer.
He is a farmer.
We are workers.
cax@ibm:~/Desktop> cat  a | sort
He is a farmer.
He is a farmer.
He is a farmer.
I'm a student.
We are workers.
You are a teacher.
cax@ibm:~/Desktop> cat  a | sort | uniq
He is a farmer.
I'm a student.
We are workers.
You are a teacher.

　　　　　　

LZ要求顺序不变　　　　　　

如果重复行挨在一起， 不用sort就可以了　　　　　　

看来用awk比较方便！　　　　　　

怎么个方便法　　　　　　

引用:

原帖由 TUDOU01 于 2007-8-11 10:36 发表
文本如下：
I'm a student.
You are a teacher.
He is a farmer.
He is a farmer.
He is a farmer.
We are workers.
将重复行找到，并删去只留一行，并且文本顺序不能改变，如何用sed实现?

用 sed 有点儿难度 　　　　　　

引用:

原帖由 li-jiahuan 于 2007-8-11 15:42 发表
怎么个方便法

用 awk 这么个方便法:

引用:

-(dearvoid@LinuxEden:Forum)-(~/tmp)-
[30959 0] ; cat file
I'm a student.
You are a teacher.
He is a farmer.
He is a farmer.
He is a farmer.
We are workers.
-(dearvoid@LinuxEden:Forum)-(~/tmp)-
[30959 0] ; awk '{ if (!seen[$0]++) { print $0; } }' file
I'm a student.
You are a teacher.
He is a farmer.
We are workers.
-(dearvoid@LinuxEden:Forum)-(~/tmp)-
[30959 0] ; bye

[ 本帖最后由 dearvoid 于 2007-8-22 12:26 编辑 ]　　　　　　

又是这种伎俩：）